Infosys Puzzles

1.There is a escalator and 2 persons move down it.A takes 50 steps and B takes 75 steps

while the escalator is moving down. Given that the time taken by A to take 1 step is equal to

time taken by B to take 3 steps. Find the no. of steps in the escalator while it is staionary.

 

Solution (not sure):

 

If A takes 1 step in one second, then B takes 3 steps in one second. If A takes t1 seconds to

take 50 steps, then B takes 150 steps in t1 seconds.

For B, to take 150 steps he requires t1 seconds,

then to take 75 steps he requires t1/2 seconds.

So now, s1=50, t1 = t1 & s2=75, t2=t1/2

ans= (s1*t2 ~ s2*t1) / (t1 ~ t2) which gives 100.

so 100 steps is the answer